With the curve
parameterized by
with
, and given the vector field
the work done by
on a particle moving on along
is given by the line integral
where
The integral is then
we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>
We know that at 8:00 a.m. there were t inches of snow in the ground.
At 5:00 p.m. there were 3t inches of snow in the ground.
Then the difference between the heights of the snow is:
3t- t = 2t
And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:
3t = 12in
t = (12in)/3 = 4 in
Replacing that in the difference of heights:
2t = 2*4in = 8in
From this, we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.
If you want to learn more about linear equations:
brainly.com/question/1884491
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Answer:
the answer is <u>C</u>.
Step-by-step explanation:
Answer:
a). 6:51
b). 6:30 am
c). 34 minutes
Step-by-step explanation:
a). Train leaves Westchester at 6:30.
From the arrival - departure table in column (2),
Arrival time of the train at middlewich = 6:51
b). Kate has to reach Southam before 9:00 am
Therefore, time of the latest train that she can catch to get to work on time is 6:30 am
By this train she can reach at 07:19 at Southam.
c). Duration of journey from Westchester to Eastwick = 06:34 - 06:00
= 00:34
≈ 34 minutes
Each year 107.2%increase of budget
first year 500 * 1.072 = 536
second year 536 * 1.072 = 574.592
third year 574.592 * 1.072 = 615.962624
..
..
sixth year 707.854392 * 1.072 = 758.819908
or you can just (1.072)^6 * 500 = 1.517639816659862 * 500 = 758.8199083299308
bingo........
