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Inessa [10]
3 years ago
6

What’s the answer ?

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

C) an obtuse triangle

Step-by-step explanation:

Since the main angle (the angle that corresponds to the longest side) is considered to measure more than 90°, it is an obtuse triangle.

AURORKA [14]3 years ago
5 0
Obtuse angle, because it’s just a big bigger than a right angle (90 degrees)
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a bag of of apples cost $5.50. How much do three bags cost if there is a 10% discount on your table scale
dangina [55]

Answer: $14.85

Step-by-step explanation:

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4 years ago
Joel is constructing a line perpendicular . He has already constructed three arcs as shown. Use the image to answer the question
IgorC [24]
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8 0
3 years ago
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Question 57 need help
prisoha [69]
Okay so first we need to find the height ofn one hay barrel. To do this we must use the equations v= h×w×l

We already know 3 out of the 4 variables in the equations, in this case we are given the volume so we must work backwards.

The equation will look like this:
10 \frac{2}{3}    = h \times (1  \frac{1}{3} ) \times 4
First we must mulitpy 4 and 1 1/3 to get 16/3. The equation will now look like:
10 \frac{2}{3}  = h \times  \frac{16}{3}
Next divide 16/3 from h then from 10 2/3 to get :
2 = h
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8 0
3 years ago
Read 2 more answers
The slope of a line passing through H (-2, 5) is -3/4. Which ordered pair represents a point on this line?
oksano4ka [1.4K]
Answer:
(6,-1)

Explanation:
The slope of the line can be calculated using the following formula:
slope = \frac{y2-y1}{x2-x1}

We are given that:
slope = -0.75
point (x1,y1) is (-2,5)

We will use each of the given points to calculate the corresponding slope, then compare the calculated slope with the given one.

For point (6,-1):
slope = \frac{-1-5}{6--2} = -0.75 ........> accepted choice

For point (2,8):
slope = \frac{8-5}{2--2} = 0.75 ........> rejected choice

For point (-5,1):
slope = \frac{1-5}{-5--2} = 4/3 ........> rejected choice

For point (1,1):
slope = \frac{1-5}{1--2} = -4/3 ........> rejected choice

Therefore, the first option is the only correct one.

Hope this helps :)
5 0
3 years ago
Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th
Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)

Where:  

A=22 g is the final amount of the radioactive element

A_{o}=800 g is the initial amount of the radioactive element  

t is the time elapsed  

h=8 min is the half life of the radioactive element  

So, we need to substitute the given values and find t from (1):  

22 g=(800 g) 2^{\frac{-t}{8 min}} (2)  

\frac{22 g}{800 g}=2^{\frac{-t}{8 min}} (3)  

\frac{11}{400}=2^{\frac{-t}{8 min}} (4)  

Applying natural logarithm in both sides:  

ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}}) (5)  

-3.593=-\frac{t}{8 min}ln(2) (6)  

Clearing t:

t=41.46 min \approx 41.5 min This is the time elapsed

7 0
3 years ago
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