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vovangra [49]
2 years ago
13

A geometric sequence can be used to describe the population of rabbits on a

Mathematics
1 answer:
vlabodo [156]2 years ago
6 0

Answer:

step 1

Find the average growth per year of the populations of rabbits farm A

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=40

average=[40-5]/2---------> 17.5

step 2

Find the average growth per year of the populations of rabbits farm B

Over the first 2 years

for t=0

numbers of rabbits=5 (is not exact)

for t=2

numbers of rabbits=30

average=[30-5]/2---------> 12.5

step 3

Compare the average growth per year of the populations of rabbits on both farms

farm A=17.5

farm B=12.5

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 5 rabbits per year.

therefore

the answer is the option C)

the average rate of population growth of rabbits in farm A is greater than average rate of population growth of rabbits in farm B by about 6 rabbits per year.

Step-by-step explanation:

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Step-by-step explanation:

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The zeros of the function are

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I hope this helps!

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Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
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Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
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p'(x) = 400 - 20x -200
0 = 200 - 20x
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Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
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What is 1 8/9 written as a improperfraction
Yakvenalex [24]
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17/9
Hoped this helped!
4 0
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