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3 years ago

10

2 What are the coordinates of the image? Rx-axis (1, 6)

2 answers:

aalyn [17]3 years ago

6 0

Go to the right 1 and then ride up 6

Gekata [30.6K]3 years ago

5 0

Answer:

over one to the right, up six

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39.6 x 5.20 show your work traditional method

fgiga [73]

Answer:

We have to multiply

⇒39.6 x 5.20 [ Using traditional method]

Traditional method: used by humans when they learnt counting and when fraction came into existence.Suppose something(Area of a field) is divided into parts and another thing(Amount of water used in irrigating the field) is divided into parts and then we have to multiply these two numbers.

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3 years ago

Select the correct answer.

Lyrx [107]

Answer:

I think it's D but I am not sure.

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2 years ago

If you increase your current quality score of 85% by 7% you will have a score of what ?

amm1812

The answer is 90.95 percent

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3 years ago

Which equation represents a line that passes through 4 6) and is parallel to the line whose equation is 3x - 4y= 6

Pachacha [2.7K]

Parallel means their slopes should equal to each other.

Thus we need to find the slope of the given line ,

Let's do it.....

$3x - 4y = 6$

Subtract sides -3x

$- 3x + 3x - 4y = - 3x + 6$

$- 4y = - 3x + 6$

Divided sides by -4

$\frac{ - 4}{ - 4}y = \frac{ - 3}{ - 4}x + \frac{6}{ - 4} \\$

$y = \frac{3}{4}x - \frac{3}{2} \\$

This is the slope-intercept of the line.

We know that the coefficient of the x in slope-intercept form , is the slope of the line.

Thus the slope of the equation which we want is :

$slope = \frac{3}{4} \\$

_________________________________

We have following equation to find the point-slope form of the linear functions.

$y - y(given \: point) = slope \times (x - x(g \: p) \: ) \\$

Now just need to put the slope and the given point in the above equation.

$y - 6 = \frac{3}{4} \times (x - 4) \\$

Multiply sides by 4

$4(y - 6) = 3(x - 4)$

$4y - 24 = 3x - 12$

Plus sides 24

$4y - 24 + 24 = 3x - 12 + 24$

$4y = 3x + 12$

Subtract sides -3x

$4y - 3x = 3x - 3x + 12$

$4y - 3x = 12$

And we're done....♥️♥️♥️♥️♥️

4 0

3 years ago

For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?

Gre4nikov [31]

The equation is separable, so solving it is trivial:

$\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt$

Integrating both sides gives

$\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}$

Given $y(0)=24$ and $y(1)=18$ , we find

$24=C$

$18=Ce^k=24e^k\implies e^k=\dfrac34\implies k=ln\dfrac34$

so the answer is E.

8 0

3 years ago

Read 2 more answers