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3 years ago

Can anyone answer this

Mathematics

1 answer:

kicyunya [14]3 years ago

6 0

I’m not sure can I you tell me

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The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

3 0

3 years ago

When using pi, do you use 3.14 or 3.141592653?

sergey [27]

Answer:

You would usually use 3.14

Step-by-step explanation:

It kind of depends on where you are using it. In an equation, pi would be used as 3.14 and the answer would be approximated. To write it anywhere else (I dont know where else you would though), you would do the pi symbol. I hope this helps.

4 0

3 years ago

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System AAA \text{\quad}start text, end text System BBB

lisabon 2012 [21]

Answer:

replace one question with itself where the same quantity is added to both sides and yes

Step-by-step explanation:

The other answer is wrong :)

4 0

3 years ago

Read 2 more answers