Answer:
C
Step-by-step explanation:
We can first move the variables to one side.
We can do this by subtracting 6x from both sides.
12x^2-6x=0
Now, we can factor out 6x.
6x(2x-1)=0
Since it equals 0, we know that 2x-1=0, or 6x=0.
This is because when ab=0, either a or b must equal 0.
So we can set both of these equal to 0 to solve.
6x=0
Divide both sides by 6.
x=0
2x-1=0
Add 1 to both sides.
2x=1
Divide both sides by 2.
x=1/2
Answer:
B: {(3,1), (7,9)}
Step-by-step explanation:
For equation 2x-y=5, we can isolate y, so it's easier to solve later:
y = 2x - 5
y = (x - 4)^2
Now, notice that both equations are equal to y, so we can set them equal to each other:
(x-4)^2 = 2x-5
x^2-8x+16 = 2x - 5
x^2-10x+21=0
Now, we can factorize by finding 2 numbers that multiply to 21 and add up to -10:
(x-3)(x-7)=0
x=3 or x=7
Since B is the only one with the x values of 3 and 7, the answer must be B.
But to further check our answer, we can plug x back to any of the equations above to check for y:
(3-4)^2 = 1
(7-4)^2 = 9
Therefore, we can confirm that the answer is B.
Sides, or lengths and widths
The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with:
Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.
