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Savatey [412]
4 years ago
13

Ryan won 60 tickets playing a game at the arcade. He gave four tickets

Mathematics
2 answers:
3241004551 [841]4 years ago
4 0

Answer:

60 tickets he gave 13 friends 4 tickets

13 friends

Step-by-step explanation:

lara31 [8.8K]4 years ago
3 0

Answer:

13 friends recieved a ticket.

Step-by-step explanation:

To solve this, we can set up an equation.

Let's say that he has x friends.

60-4x=8

Now we can solve this equation by isolating x.

First we can subtract 60 from both sides.

-4x=-52

Divide both sides by -4.

x=13

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8.
lukranit [14]

Answer:

4

Step-by-step explanation:

The y-coordinate of the point where both lines intersect will give us the same solution for x.

At y = 4, both equations will have a corresponding x-value of 1.

Therefore, the value of y that that will make both equations have the same solution of x is 4.

7 0
3 years ago
Express the ratio in its simpilest form<br><br> 4:2:2
kotykmax [81]
The ratio in simplest form would be 1:2:2.
5 0
3 years ago
What are the zeros of the polynomial function?
Genrish500 [490]

Hello from MrBillDoesMath!

Answer:

x = 2 and 10


Discussion:

Approach 1:

20 = (-10)*(-2) and  (-10) + (-2) = -12 the coefficients of the polynomial. Hence

x^2 -12x + 20 = ( x- 2) * ( x-10)


Approach 2:

From the quadratic formula ( a = 1, b = -12, c = 20)

x =    (  -(-12) +\- sqrt( ((-12)^2 - 4*1*20) )  /  (2 * 1)

   =    ( 12 +\- sqrt( 144-80)  ) /2

  =   (12 +\-  sqrt(64) ) /2

  =  (12 +\- 8 ) /2


x  = ( 12 + 8) /2 = 20/2 = 10

or

x = ( 12 - 8)/ 2 = 4/2 = 2



Thank you,

MrB

5 0
4 years ago
Read 2 more answers
Work out m and c for the line:2y+6x=4<br><br><br>​
Ray Of Light [21]

Answer:

m = 1/3, c = 2

Step-by-step explanation:

Explained in the paper

8 0
3 years ago
Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

d = \sqrt{89

d = 9.4

Solving (b): The radius;

In (a), we have:

r = 3 --- circle P

r = 2 --- circle Q

By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

4 0
3 years ago
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