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3 years ago

A number is as much greater than 21 as it is less than 75 .find the number

Mathematics

1 answer:

laiz [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Let number is x greater than 21 and x less than 71.

Now, according to question,

21+x=71−x

2x=50

x=25

So, required number is 21+x=21+25=46.

Alternatively,

The required number would be the average or mean of 21 and 71.

So, required number =

(21+71)

=46.

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Step-by-step explanation:

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$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

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Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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A number is as much greater than 21 as it is less than 75 .find the number​

A number is as much greater than 21 as it is less than 75 .find the number