Question

A spinner is divided into 10 equal sections numbered 1 through 10. If the arrow is spun twice, what is the probability the first number will be even and the second number will be odd?

Answer 1

Probability of first number being even : 5 even numbers...10 equal sections...probability is 5/10 or 1/2

probability of 2nd number being odd : 5 odd numbers...10 equal sections...so probability of both is 5/10 or 1/2

probability of both occurring : 1/2 * 1/2 = 1/4 <== (or 25% if u need it in percent form or 0.25 if u need it in decimal form)

Answer 2

$\text{p(n%2) = 0 AND p(n%2)} \neq 0$
$\text{Event 1} = \frac{5}{10} = 0.5$
$\text{Event 2} = \frac{5}{10} = 0.5$
$\text{Event 1 * Event 2} = 0.5 * 0.5 = 0.25 \text{$