A spinner is divided into 10 equal sections numbered 1 through 10. If the arrow is spun twice, what is the probability the first
number will be even and the second number will be odd?
2 answers:
Probability of first number being even : 5 even numbers...10 equal sections...probability is 5/10 or 1/2
probability of 2nd number being odd : 5 odd numbers...10 equal sections...so probability of both is 5/10 or 1/2
probability of both occurring : 1/2 * 1/2 = 1/4 <== (or 25% if u need it in percent form or 0.25 if u need it in decimal form)
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