Two adjacent, supplementary angles form a line?

Mathematics

1 answer:

omeli [17]3 years ago

8 0

obtuse because it all adds up to 180 degrees

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Josh and Katya both work at a library making $9 per hour if Katya work seven more hours than Josh last week and they made $279 c

lora16 [44]

Answer:

19 hours

Step-by-step explanation:

You have 279. First, devide the 279 by 9(dollar amount).

279/9 = 31

So combined they work 31 hours. Subtract 7 from this, since we know Katya worked 7 extra hours. Youll now have 24. (31-7 = 24)

Next, divide this number in half, which will get you what they both worked before Katya worked an extra 7 hours.

24/2 = 12.

Now that we know they both worked 12 hours, we can just add back the 7 hours Katya worked.

12+7 = 19.

So the answer to how many hours katya worked will be:

<u>19 hours</u>

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3 years ago

1. Nasim thinks of a number.

mrs_skeptik [129]

Step-by-step explanation:

5x-16 = 3 (10+x)

=> x= 23

7 0

2 years ago

Josh stopped at a booth at the fair. The prices of the items being sold were posted on a sign like the one seen below. Josh was

Vikki [24]

Answer:

i need the full sing to determine the answer

3 0

3 years ago

Given cos(4x)+2<br><br> Find: Period, Shift, & Range

Yuki888 [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}\qquad$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's see

$\bf \begin{array}{llccll}
cos(&4x&+0)&+2\\
&\uparrow &\uparrow &\uparrow \\
&B&C&D
\end{array} 
\\\\\\
period\qquad \cfrac{2\pi }{B}\implies \cfrac{2\pi }{4}\implies \cfrac{\pi }{2}
\\\\\\
\textit{horizontal/phase shift}\qquad \cfrac{C}{B}\implies \cfrac{0}{4}\implies 0\impliedby none
\\\\\\
\textit{vertical shift}\qquad D=+2\impliedby \textit{2 units up}$

now the range, how far up and down it goes on the y-axis

well, for the graph of cos(x), the range is, goes up to 1, down to -1, is all,

the midline is at 0

now, with a vertical shift of 2 upwards, it moves the midline by 2 units, used to be at 0, now is at y = 2, but the amplitude never changed, is goes up and down still one unit,

but with the midline at 2, goes up to 3 and down to 1, so the range is 3 ⩽ y ⩽ 1

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4 years ago

360,450,540 what comes next?

Talja [164]

It is an arithmetic sequence with each number 90 more than the previous number so the next number is 630

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3 years ago