*. Which of the tables below shows the same linear relationship as the equation

Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

7 0

3 years ago

Help I need help with this one

andrey2020 [161]

THE CORRECT ANSWER IS D 1/6

8 0

3 years ago

Six years less than Tracey's age as an expression

likoan [24]

Answer:

T-6=X

Step-by-step explanation:

Tracey = T

X = Awnser

If we are subtracting six from Tracey's age, you would subtract six from T

since we don't know Tracey's age, it is represented by T.

Hope this Helps!

4 0

3 years ago

Help me .......................................

SpyIntel [72]

Answer:

X^3 AS THE NUMERATOR 8 AS THE DENOMINATOR

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

Romashka [77]

Answer:

A.The mean would increase.

Step-by-step explanation:

Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.

Presence of outliers effect the measures of central tendency.

The measures of central tendency are mean, median and mode.

The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.

Effect of outliers on mean, median and mode:

Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
Median: The presence of outliers in a data set has a very mild effect on the median of the data.
Mode: The presence of outliers does not have any effect on the mode.

The mean of the test scores without the outlier is:

$\bar{x}=\frac{Total of the observations-Outlier value}{n-1} \\=\frac{(86*16)-72}{15} \\=\frac{1304}{15}\\ =86.9333$

*Here <em>n</em> is the number of observations.

So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.

The mean increased.

Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.

Conclusion:

After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.

Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.

4 0

3 years ago