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aliina [53]
2 years ago
10

*. Which of the tables below shows the same linear relationship as the equation

Mathematics
1 answer:
GrogVix [38]2 years ago
7 0

Answer:

B

Step-by-step explanation:

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* PLEASE HELP *
saul85 [17]

Answer:

C is the only correct answer

4 0
2 years ago
Find an equation for the line perpendicular to the line 8x - 6y = -2 having the same y-intercept as - 6x + 2y = 4.
MissTica
The answer is
3 x - y + 2 = 0






Hope this helps :)
4 0
2 years ago
Read 2 more answers
What is the solution to this equation 5x -8(x + 5)= 6-3x
Solnce55 [7]

Answer:

no solution

Step-by-step explanation:

5x - 8(x + 5) = 6 - 3x

Remember to follow PEMDAS. Note the equal sign, what you do to one side, you do to the other.

First, distribute -8 to all terms within the parenthesis

-8(x + 5) = (-8)(x) + (-8)(5) = -8x - 40

5x - 8x - 40 = 6 - 3x

Isolate the variable (x). Add 3x & 40 to both sides

5x - 8x (+3x) - 40 (+40) = 6 (+40) - 3x (+3x)

5x - 8x + 3x = 6 + 40

Simplify. Combine like terms

(5x - 8x + 3x) = (6 + 40)

0 = 46 ; False 0 ≠ 46 ∴ no solution is your answer

~

8 0
3 years ago
Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due
ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

        Formula :   d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

      Formula : D=\sqrt{(x2-x1)^2+(y2-y1)^2}

⇒                     D = \sqrt{20^2t^2+15(t-1)^2}

Now let           F(t) = D^2(t)

                ∵    F'(t) = 800t + 450(t-1) =  1250t -450\\F'(t) =0

⇒                     t= 450/1250

⇒                     t= .36 hours

⇒                       = 21 min 36 sec

Since F"(t)=0,

∴ This time gives us a minimum.

Thus, The two boats will closet together at 2:21:36 pm.

3 0
3 years ago
Simplify (3x2 – 4x – 1) + (8x2 – x + 6)
abruzzese [7]

Answer:

11x^{2} -5x+5

Step-by-step explanation:

3x^{2}-4x-1+8x^{2} -x+6

3x^{2}+8x^{2}-4x-x-1+6

Combine like terms

11x^{2}-5x +5

6 0
3 years ago
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