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Leviafan [203]
4 years ago
7

Is it arithmetic or geometric, and solve for n ( basically what is the formula and the sequence derived?)

Mathematics
2 answers:
Alex17521 [72]4 years ago
6 0

Answer:

It is geometric with common ratio 0.75 .

The explicit formula for the sequence is a_n=256 \cdot (0.75)^{n-1}.

The 7th term is a_7 which is 45.5625 .

Step-by-step explanation:

It is arithmetic if you can add/subtract the same number to get from term to the term after.  In arithmetic sequence, the number you can add to get from term to term after is called the common difference. It is called common difference because it is the same number over and over.  

It is geometric if term divided previous term is the same number each time.  This is called a common ratio.  

Let's test to see if it is arithmetic.

If it is arithmetic, all of the following will have the same difference:

192-256=?

144-192=?

----------------------

192-256=-64

144-192=-48

These aren't the same number.  The sequence is not arithmetic.

Let's test to see if is geometric.

If it is geometric, all of the following will have the same ratio:

192/256=?

144/192=?

---------------------------

192/256=3/4 (or .75)

144/192=3/4 (or .75)

These are the same number.  The sequence has a common ratio and is therefore geometric.

The explicit form for the equation of a geometric sequence is:

a_n=a_1 \cdot r^{n-1}

where a_1 is the first term and r is the common ratio.

We have a_1=256 while r=.75.

The explicit form is:

a_n=256 \cdot (.75)^{n-1}

The 7th term can be found by replacing n with 7. Like so:

a_7=256 \cdot (.75)^{7-1}

Putting right hand side into calculator reveals the 7th term is:

a_7=45.5625

gladu [14]4 years ago
5 0
It is geometric because it is a sequence of multiplying a constant number, in this case the constant is 0.75. You find the constant by dividing one term by the term before it, so 192/256 or 144/192, they would both give you the answer of 0.75. To find n7 (t7 is they way we named it) you use the formula tn=t1xr^(n-1)
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1)  288.8 km due North

2)  144.9 km due East

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Step-by-step explanation:

<u>Bearing</u>: The angle (in degrees) measured clockwise from north.

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

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-----------------------------------------------------------------------------------------------

Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

<u>Question 1</u>

To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

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<u>Question 2</u>

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\implies \sf Bearing=180^{\circ}+26.64077...^{\circ}

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