Work out 5 9 − 1 3 Give your answer in its simplest form.

Mathematics

1 answer:

Ne4ueva [31]2 years ago

5 0

4 7/13
I believe that thats the answer

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Ashton made contributions to a Roth IRA over the course of 32 working years. His contributions averaged $2,400 annually. Ashton

enyata [817]

The formula of the future value of an annuity ordinary is
Fv=pmt [(1+r)^(n)-1)÷r]
Fv future value?
PMT 2400
R 0.08
T 32 years
Fv=2,400×((1+0.08)^(32)−1)÷(0.08)
Fv=322,112.49
Now deducte 28% the tax bracket from the amount we found
annual tax 2,400×0.28 =672 and tax over 32 years is 672×32 =21,504. So the effective value of Ashton's Roth IRA at retirement is 322,112.49−21,504=300,608.49

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3 years ago

The edge of a cube whose volume is 1728 cm 3

mamaluj [8]

Answer:

12 cm

Step-by-step explanation:

This would be the cubic root of 1728

= 12 cm

( 1729 is known as Ramanajan's number. Look it up - it's interesting)

3 0

3 years ago

There are 6 times as many males as females on the maths course at university. What fraction of the course are male? Give your an

Mumz [18]

Assign x as the number of females.

Since makes are six times more: 6x is the male variable.

In total there are 7x students.

So the fraction for males is : 6/7

There's no way to simplify further because there's no term common to both the denominator/numerator.

Answer: 6/7

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3 years ago

If Archie has 100 balls, and 39 of those are tennis balls, what percent of the total balls are tennis balls?

docker41 [41]

39/100=0.39

0.39*100=39

%39

6 0

3 years ago

Cos^(2)x=(cscxcosx)/(tanx+cotx)

bixtya [17]

$\cos^2 x = \dfrac{\csc x \cos x}{\tan x + \cot x}$

$\cos^2 x = \dfrac{\csc x \cos x}{\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin x}{\cos x} \times 
\frac{\sin x}{\sin x} + \frac{\cos x}{\sin x} \times \frac{\cos x}{\cos 
x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{\sin^2 x}{\sin x \cos x} + \frac{\cos^2 x}{\sin x \cos x}}$

$\cos^2 x = \dfrac{\csc x \cos x}{\frac{1}{\sin x \cos x}}$

$\cos^2 x = \csc x \cos x \sin x \cos x$

$\cos^2 x = \dfrac{1}{\sin x} \cos x \sin x \cos x$

$\cos^2 x = \cos^2 x$

6 0

3 years ago