In a certain county in 2013, it was thought that 50% of men 50 years old or older had never been screened for prostate cancer.
1 answer:
Answer:
120,0.60,100
Step-by-step explanation:
Given that in a certain county in 2013, it was thought that 50% of men 50 years old or older had never been screened for prostate cancer.
Suppose a random sample of 200 of these men shows that 120 of them had never been screened.
a) the observed frequency = 120
b) The observed proportion of men who said they had not been screened
=
c) Expected number in the sample to say they had never been screened if 50% is the correct rate
= np
=
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Answer:
the answer is =-3±/2
Step-by-step explanation:
In both cases,
(as a consequence of the interesecting secant-tangent theorem)
So we have
10.
(omit the negative solution because that would make at least one of AB or AD have negative length)
11.
(again, omit the solutions that would give a negative length for either AB or AD)
Answer:
If we compare the p value and a significance level for example we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.
Step-by-step explanation:
Data given and notation
represent the average lateral recumbency for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
represent the significance level for the hypothesis test.
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to apply a left tailed test.
What are H0 and Ha for this study?
Null hypothesis:
Alternative hypothesis :
Compute the test statistic
The statistic for this case is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
We can replace in formula (1) the info given like this:
The degrees of freedom are given by:
Give the appropriate conclusion for the test
Since is a one side left tailed test the p value would be:
Conclusion
If we compare the p value and a significance level for example we see that
so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.