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uranmaximum [27]
3 years ago
5

In a certain county in​ 2013, it was thought that​ 50% of men 50 years old or older had never been screened for prostate cancer.

Suppose a random sample of 200 of these men shows that 120 of them had never been screened.
a. What is the observed frequency of men who said they had not been​ screened?b. What is the observed proportion of men who said they had not been​ screened?c. What is the expected number in the sample to say they had never been screened if​ 50% is the correct​ rate?
Mathematics
1 answer:
joja [24]3 years ago
8 0

Answer:

120,0.60,100

Step-by-step explanation:

Given that in a certain county in​ 2013, it was thought that​ 50% of men 50 years old or older had never been screened for prostate cancer.

Suppose a random sample of 200 of these men shows that 120 of them had never been screened.

a) the observed frequency = 120

b) The observed proportion of men who said they had not been​ screened

=\frac{120}{200} \\=0.60

c) Expected number in the sample to say they had never been screened if​ 50% is the correct​ rate

= np

= 200*0.50=100

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Ulleksa [173]
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myrzilka [38]

Answer:

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3 years ago
Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of t
kati45 [8]

Question:

Morgan is playing a board game that requires three standard dice to be thrown at one time. Each die has six sides, with one of the numbers 1 through 6 on each side. She has one throw of the dice left, and she needs a 17 to win the game. What is the probability that Morgan wins the game (order matters)?

Answer:

1/72

Step-by-step explanation:

<em>Morgan can roll a 17 in 3 different ways. The first way is if the first die comes up 5, the second die comes up 6, and the third die comes up 6. The second way is if the first die comes up 6, the second die comes up 5, and the third die comes up 6. The third way is if the first die comes up 6, the second die comes up 6, and the third die comes up 5. For each way, the probability of it occurring is  1/6 x 1/6 x 1/6 = 1/216. Therefore, since there are 3 different ways to roll a 17, the probability that Morgan rolls a 17 and wins the game is  1/216 + 1/216 + 1/216 = 3/216 = 1/72</em>


<em>I had this same question on my test!</em>


<em>Hope this helped! Good Luck! ~LILZ</em>


3 0
3 years ago
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