The answer is C because it fits the formula a+b=c
2+4=6
Answer:
hxdjgcfmv,hjb.kn
Step-by-step explanation:
hrzdxjcgfmv,guvmcdcfvmtfbudufuv,gh
Answer:
![\large\boxed{\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-30%5C%5C-10%26-2%5Cend%7Barray%7D%5Cright%5D%7D)
Step-by-step explanation:
![X-3\left[\begin{array}{ccc}2&-8\\-4&2\end{array}\right] =\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}(3)(2)&(3)(-8)\\(3)(-4)&(3)(2)\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]](https://tex.z-dn.net/?f=X-3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%283%29%282%29%26%283%29%28-8%29%5C%5C%283%29%28-4%29%26%283%29%282%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D)
![X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]\\\\X=\left[\begin{array}{ccc}4+6&(-6)+(-24)\\2+(-12)&-8+6\end{array}\right]\\\\X=\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]](https://tex.z-dn.net/?f=X-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2B6%26%28-6%29%2B%28-24%29%5C%5C2%2B%28-12%29%26-8%2B6%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-30%5C%5C-10%26-2%5Cend%7Barray%7D%5Cright%5D)
Answer:
0.0636
Step-by-step explanation:
The probability the first die has twelve sides is 4/11.
The probability the second die has twelve sides is 3/10.
The probability the third die does not have twelve sides is 7/9.
The probability the fourth die does not have twelve sides is 6/8.
The probability of all four events is:
4/11 × 3/10 × 7/9 × 6/8 = 0.0636
Answer:
d.yes because P(Grade 12/PClub Membership) = P(Grade 12)
Step-by-step explanation:
