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horrorfan [7]
2 years ago
15

HOW MANY 7 DIGIT TELEPHONE NUMBERS ARE POSSIBLE IF THE FIRST DIGIT CANNOT

Mathematics
1 answer:
lyudmila [28]2 years ago
6 0

Answer:

there are 8 million different phone numbers whose phone numbers whose digits aren't 0 or 1

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If you mean x^2=36, then the answer is -6 or 6
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3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
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3 years ago
Convert 7.23 (3 reapting) to a fraction
Svetllana [295]

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ROUND YOUR ANSWER TO THE NEAREST TENTH
Darya [45]

Answer:

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Use pythagorean theorem

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cestrela7 [59]

Answer:

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Use the point (1,3) and substitute it into the equation.

Point-slope form: y-y1 = m(x-x1)

y-3 = -4 (x-1)

4 0
3 years ago
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