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Marina CMI [18]
3 years ago
6

The set of real numbers that are greater than negative five

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

-4 -3 -2 -1 0 1 2 3 4 5 etc.

x > -5

Step-by-step explanation:

Basically any number that doesn't exceed -5 and is a rational/real number

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How many roots does this has?<br>x^2+(2√5x)+2x=-10​<br>find Discriminant
Alexxandr [17]

Given:

The equation is

x^2+(2\sqrt{5})+2x=-10

To find:

The number of roots and discriminant of the given equation.

Solution:

We have,

x^2+(2\sqrt{5})x+2x=-10

The highest degree of given equation is 2. So, the number of roots is also 2.

It can be written as

x^2+(2\sqrt{5}+2)x+10=0

Here, a=1, b=(2\sqrt{5}+2), c=10.

Discriminant of the given equation is

D=b^2-4ac

D=(2\sqrt{5}+2)^2-4(1)(10)

D=20+8\sqrt{5}+4-40

D=8\sqrt{5}-16

D\approx 1.89>0

Since discriminant is 8\sqrt{5}-16\approx 1.89, which is greater than 0, therefore, the given equation has two distinct real roots.

3 0
3 years ago
Help please is for now
zmey [24]
Answer: 5

Steps:
5x - 2y = 30
5(8) - 2y = 30
40 - 2y = 30
-2y = 30 - 40
-2y = -10
y = -10/-2
y = 5

I would appreciate the brainliest if this answer was correct and the steps were clear and helpful! :)
3 0
3 years ago
Can someone help me with this math homework please!
alisha [4.7K]

Answer:

X1 = 2 Y1 = -5

Step-by-step explanation:

math simple slope

5 0
3 years ago
The opposite angles of a rhombus are equal true or flase?
Scrat [10]
I believe the answer is True
6 0
3 years ago
Read 2 more answers
Someone please help and and make sure the answer is right :)
marishachu [46]
6, it’s equal to 47, so 7(6)+5=47
7 0
3 years ago
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