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Marina CMI [18]
3 years ago
6

The set of real numbers that are greater than negative five

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

-4 -3 -2 -1 0 1 2 3 4 5 etc.

x > -5

Step-by-step explanation:

Basically any number that doesn't exceed -5 and is a rational/real number

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A

Step-by-step explanation:

Given

y - 2x - 8 = 0 ( add 2x + 8 to both sides )

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PQ = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

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PQ = \sqrt{(-2-(-8))^2+(4-(-8))^2}

      = \sqrt{(-2+8)^2+(4+8)^2}

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       = \sqrt{36} × \sqrt{5}

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Point Form:

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Equation Form:

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