Anybody help me out??????
2 answers:
You might be interested in
Answer:
59.98
Step-by-step explanation:
To find the average of a set of numbers, we sum them all together and divide them by the size of the set. Here, we start out with 11 IQ scores. We don't know what they are, but we can still set up an equation with the information we do have. Let's call the sum of those 11 score <em>s</em>. The average must be s/11, which we know is 101.5. With that, we can set up and solve and equation for <em>s</em>:
Let's call the score of the reality TV star <em>r</em>. If we add their score to the set, we now have <em>12</em> scores. The sum of those scores is gonna be the sum of the previous scores, 1116.5, plus the reality TV star's score, r. To find the average, we divide the sum by 12. Finally, we're told that this average is exactly 98.04. Putting all of this into an equation gives us
We can now solve for r algebraically, first by multiplying both sides by 12:
And then subtracting 1116.5 from both sides:
Answer:
No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Step-by-step explanation:
Assuming: the function is in [0,1]
And rewriting it for the sake of clarity:
Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer
1) A function is considered to be differentiable if, and only if both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:
2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]
The limit to the left
g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)
3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R
Because this is the same as to calculate the limit from the left and right side, of g(x).
This is what the Bilateral Theorem says: