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irina [24]
3 years ago
14

I need help plzzzzzzzzz

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

1 2 5 . 6 9

1 2 5 . 6 7 0

125.69 Would be Greater.

Step-by-step explanation:

First number to the right of the decimal is the tenths place 2nd number would be hundredths and you'd increase etc.

You might be interested in
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is
Volgvan

Answer:

Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting.

It is believed that the machine is under filling the bags. A 21 bag sample had a mean of 429 grams with a variance of 289.

<u><em>Let </em></u>\mu<u><em> = mean weight bag filling capacity of machine.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 429 grams

             s = sample standard deviation = \sqrt{289} = 17 grams

             n = sample of bags = 21

So, <u><em>test statistics</em></u>  =  \frac{429-430}{\frac{17}{\sqrt{21} } }  ~ t_2_0   

                               =  -0.269

<em>Now at 0.01 significance level, the t table gives </em><u><em>critical value of -2.528 at 20 degree of freedom</em></u><em> for left-tailed test. Since our test statistics is higher than the critical value of t as -0.269 > -2.528, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the machine is not under filling the bags.

3 0
3 years ago
What is the equation of the line that passes through the point (5, 4) and has a slope<br> of<br> 6/5
Sati [7]

Answer:

y=6/5x-2

Step-by-step explanation:

y=mx+C

Y=6/5X+C

4=6+c

c=-2

y=6/5x-2

5 0
3 years ago
Please help me do number 3 and number 4
Marina86 [1]
Hello : 
let : A(0,3)    B(4,8)
<span>the slope is :   (YB - YA)/(XB -XA)
</span>(8-3)/(4-0) = 5/4
same method for 4
3 0
3 years ago
Is it, A, B, C, Or D?
trasher [3.6K]

Answer:

C

Step-by-step explanation:

6(2m+5n)

12m+30n

Jacob had multiplied 6 to 2m right which is 12m but multiplied 6 and 5n wrong as he thought it was 11n yet it is 30n.

4 0
3 years ago
F(x) =
Oksana_A [137]

9514 1404 393

Answer:

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

  d(u/v) = (v·du -u·dv)/v²

__

  f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

  f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

  f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

  f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

4 0
3 years ago
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