All categories

3 years ago

9≥−2m+2−3 i need for this my math test

Mathematics

2 answers:

icang [17]3 years ago

4 0

Step-by-step explanation:

9> -2m+2-3

9> -2m-1

9+1> -2m

10> -2m

10 > m

-2

-5> m

hope it helps..

ArbitrLikvidat [17]3 years ago

3 0

Answer:

The answer for that is m≥−5

You might be interested in

Write the first four terms of a sequence given the recursive rule below:

777dan777 [17]

Answer:

The first four terms of the sequence is : A) 7, 17, 37, 77.

Step-by-step explanation:

The given function f(n) = 2 x f(n − 1) + 3

Also, f(1)= 7

FOR n= 2

f(2) = 2 x f(2-1) + 3 = 2 x f(1) + 3

= (2 x 7) + 3 = 14 + 3 = 17

⇒f(2) = 17

FOR n= 3

f(3) = 2 x f(3-1) + 3 = 2 x f(2) + 3

= (2 x 17) + 3 = 34 + 3 = 37

⇒f(3) = 37

FOR n= 4

f(4) = 2 x f(4-1) + 3 = 2 x f(3) + 3

= (2 x 37) + 3 = 74 + 3 = 77

⇒f(4) =77

So, the first four terms of the sequence are 7, 17, 37, 77.

A) is the correct option.

5 0

3 years ago

3 +6=4+ cam someone please explain this to me?

Neko [114]

3+6 =9 so ? has to equal 5. so 3+6=4+5

5 0

3 years ago

Read 2 more answers

the equation is -2x² = 4-3 (x + 1) and the question is justify that it is a 2nd degree equation with the unknown x complete.

Serggg [28]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

-2x² = 4-3 (x + 1)

-2x² = 4-3x-3

-2x² = -3x -7

0 = 2x² -3x -7

We know that the degree of the equation is the highest power of x variable in the given equation.

In the equation 0 = 2x² -3x -7 the highest power of x variable in the given equation is 2.

Thus, the degree of the equation is 2.

Also in the equation 0 = 2x² -3x -7, the unknown variable is 'x'.

Let us determine the value 'x'

2x² -3x -7 = 0

Add 7 to both sides

$2x^2-3x-7+7=0+7$

$2x^2-3x=7$

Divide both sides by 2

$\frac{2x^2-3x}{2}=\frac{7}{2}$

$x^2-\frac{3x}{2}=\frac{7}{2}$

Add (-3/4)² to both sides

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{7}{2}+\left(-\frac{3}{4}\right)^2$

$x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{65}{16}$

$\left(x-\frac{3}{4}\right)^2=\frac{65}{16}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{3}{4}=\sqrt{\frac{65}{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{\sqrt{16}}$

$x-\frac{3}{4}=\frac{\sqrt{65}}{4}$

Add 3/4 to both sides

$x-\frac{3}{4}+\frac{3}{4}=\frac{\sqrt{65}}{4}+\frac{3}{4}$

$x=\frac{\sqrt{65}+3}{4}$

similarly solving

$x-\frac{3}{4}=-\sqrt{\frac{65}{16}}$

$x=\frac{-\sqrt{65}+3}{4}$

So the solution of the equation will have the values of x such as:

$x=\frac{\sqrt{65}+3}{4},\:x=\frac{-\sqrt{65}+3}{4}$

6 0

3 years ago

If 2l-18=5l+18, what is the value of t?

satela [25.4K]

3=69.
There is no value between them, except they can be both divided by 3.

8 0

4 years ago

Rachel bought a corn dog and three candy bars for $5.75. Allison bought two corn dogs and two candy bars for $7.50.

andreev551 [17]

Answer:

Step-by-step explanation:

4 0

3 years ago