Answer:
Step-by-step explanation:
Find the slope of the line
(x₁ , y₁) = (6 , 8) & (x₂ , y₂) = (0 , 5)
![Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{5-8}{0-6}\\\\=\frac{-3}{-6}\\\\=\frac{1}{2}](https://tex.z-dn.net/?f=Slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B5-8%7D%7B0-6%7D%5C%5C%5C%5C%3D%5Cfrac%7B-3%7D%7B-6%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D)
m = 1/2 ;(x₁ , y₁) = (6 , 8)
y - y₁ = m(x - x₁)
![y - 8 = \frac{1}{2}(x - 6)\\\\y - 8 =\frac{1}{2}x -\frac{1}{2}*6\\\\y - 8 =\frac{1}{2}x- 3\\\\y = \frac{1}{2}x - 3 + 8\\\\y = \frac{1}{2}x + 5](https://tex.z-dn.net/?f=y%20-%208%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28x%20-%206%29%5C%5C%5C%5Cy%20-%208%20%3D%5Cfrac%7B1%7D%7B2%7Dx%20-%5Cfrac%7B1%7D%7B2%7D%2A6%5C%5C%5C%5Cy%20-%208%20%3D%5Cfrac%7B1%7D%7B2%7Dx-%203%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-%203%20%2B%208%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20%2B%205)
The first answer of part A is 32
So 4y means you have to multiply 4 by y, which is 20 since 4x5=20
And then you add 12, which is 32.
The second answer to part A is 40
With the second question of part a, the expression is basically saying 4 times whatever 5+3 is. So 5+3= 8, and 4(8) is 40
For part B, they are equivalent because let’s pretend y=2. 12+4y= 20. And then 4(y+3) would equal 20 because 4(2)=8 and 4(3)=12 and 8+12=20. This might not be the answer that your teacher is looking for, but it’s still a right answer so technically they can’t say it’s wrong unless you have a super unfair teacher
I found the answer. hehehehehehehehrheehrhrh
38+38+49+11.5x≤171
125+11.5x≤171
11.5x≤46
x≤4
Answer:She could buy 4 pieces of jewlery
Hope this helps:)
Answer: $107,836.69 or about $107,837 (to the nearest dollar)
Step-by-step explanation:
Formula to the accumulated amount received after investing principal amount (P) at rate of interest (r) compounded monthly for t months :
![A=P(1+\dfrac{r}{12})^{t}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cdfrac%7Br%7D%7B12%7D%29%5E%7Bt%7D)
As per given , A = $130,000
r= 7.5% = 0.075
t= 30 months
Now,
![130000=P(1+\dfrac{0.075}{12})^{30}\\\\\Rightarrow 130000=P(1+0.00625)^{30}\\\\\Rightarrow 130000=P(1.00625)^{30}\\\\\Rightarrow 130000=P \times1.20552661036\\\\\Rightarrow\ P=\dfrac{130000}{1.2055266}=107,836.69](https://tex.z-dn.net/?f=130000%3DP%281%2B%5Cdfrac%7B0.075%7D%7B12%7D%29%5E%7B30%7D%5C%5C%5C%5C%5CRightarrow%20130000%3DP%281%2B0.00625%29%5E%7B30%7D%5C%5C%5C%5C%5CRightarrow%20130000%3DP%281.00625%29%5E%7B30%7D%5C%5C%5C%5C%5CRightarrow%20130000%3DP%20%5Ctimes1.20552661036%5C%5C%5C%5C%5CRightarrow%5C%20%20%20P%3D%5Cdfrac%7B130000%7D%7B1.2055266%7D%3D107%2C836.69)
Hence he need to invest $107,836.69 .