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Butoxors [25]
3 years ago
11

1 1/3 x 5/8 A.3/4 B.4/5 C.5/6 D.5/8​

Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

c.5/6

Step-by-step explanation:

1 1/3 x 5/8  = 4/3 x  5/8

first multiply both numerator and d enumerator

then we get

20/ 24

divide both numerator and  d enumerator with 4

simplify that

=5/6

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18. A glasscutter needs to cut rectangular pieces of
ololo11 [35]

For the cut glass pieces to be rectangular in shape, the glass cutter should ensure:

  1. All four interior angles = 90° each.
  2. Opposite sides are parallel and equal to each other.
  3. Diagonals should be of the same length and should bisect each other.

<h3>Properties of a Rectangle</h3>
  • All four angles of a rectangle are 90° each.
  • There are two pairs of parallel sides that are equal in length.
  • The diagonals bisect each other and are of equal length.

Thus, to ensure the cut glass pieces are rectangular in shape, he should ensure the following:

  1. Make the four interior angles 90° each.
  2. The opposite sides should be parallel and equal to each other.
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Learn more about properties of rectangle on:

brainly.com/question/2835318

4 0
2 years ago
7
Anton [14]

Answer:

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7 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

5 0
3 years ago
What kind of number is 0.87 <br><br> rational or irrational
grigory [225]

Answer: it is rational

Step-by-step explanation:

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