Using the pythagorean identity, we can find the value of sin(A)
cos^2(A) + sin^2(A) = 1
(12/13)^2 + sin^2(A) = 1
144/169 + sin^2(A) = 1
sin^2(A) = 1 - 144/169
sin^2(A) = 169/169 - 144/169
sin^2(A) = (169 - 144)/169
sin^2(A) = 25/169
sin(A) = sqrt(25/169)
sin(A) = 5/13
Which is then used to find tan(A)
tan(A) = sin(A)/cos(A)
tan(A) = (5/13) divided by (12/13)
tan(A) = (5/13)*(13/12)
tan(A) = (5*13)/(13*12)
tan(A) = 5/12
The final answer is 5/12
Search it up and you shall find an answer believe me it is there
Answer:
Area of circle A =113.14 mm²
Area of circle b = 314.29 mm²
Area of circle C = 452.57 mm²
Area of circle A = 254.57 mm²
2.25 times
Step-by-step explanation:
Area of a circle = nr²
where n = 22/7
r = radius
Circle A's radius = 6mm
Circle B's radius = 6mm + 4mm = 10mm
Circle C's radius = 10mm + 2mm = 12mm
Circle D's radius = 12mm - 3mm = 9mm
Area of circle A = (22/7) x 6² = 113.14 mm²
Area of circle b = (22/7) x 10² = 314.29 mm²
Area of circle C = (22/7) x 12² = 452.57 mm²
Area of circle A = (22/7) x 9² = 254.57 mm²
Number of times the area of circle D is greater than that circle A = Area of circle D / Area of circle A
254.57 mm² / 113.14 mm² = 2.25 times