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Savatey [412]
3 years ago
10

Solve for y. 6/5=3y plz answer

Mathematics
2 answers:
tamaranim1 [39]3 years ago
6 0

Answer:

shown and pictured all work

liberstina [14]3 years ago
4 0

Answer:

y = 2/5

Step-by-step explanation:

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What is the vertical asymptote of this function?
liraira [26]

Answer:

D

Step-by-step explanation:

If y = log x is the basic function, let's see the transformation rule(s):

Then,

1. y = log (x-a) is the original shifted a units to the right.

2. y = log x + b is the original shifted b units up

Hence, from the equation, we can say that this graph is:

** 2 units shifted right (with respect to original), and

** 10 units shifted up (with respect to original)

<u><em>only, left or right shift affects vertical asymptotes.</em></u>

Since, the graph of y = log x has x = 0 as the vertical asymptote and the transformed graph is shifted 2 units right (to x = 2), x = 2 is the new vertical asymptote.

Answer choice D is right.

7 0
3 years ago
Place the steps for finding f(x) in the correct order.
Naily [24]
0
The answer is C
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Someone told me
8 0
2 years ago
Read 2 more answers
Luke's bill for breakfast at a restaurant was $80. He left a 20% tip. What was the amount of
Alexandra [31]

Answer:

$16

Step-by-step explanation:

Multiply $80 dollars by 20% or .2.

You should get $16.

A tip for the future is to move the decimal point to the left twice.

ie. 60%=0.6, 175%=1.75, 3%=0.03

6 0
3 years ago
Please help me answer these. Its all about upper and lower bounds.
sergeinik [125]

Answer:

red question= 8.5 yellow question=4.25

Step-by-step explanation:

5 0
3 years ago
How many distinct pairs of perfect squares differ by 35? (the pair $a, b$ is the same as the pair $b, a$.)?
Phantasy [73]
35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35

One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
5 0
4 years ago
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