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valentina_108 [34]
3 years ago
6

Which of the following elements would most likely form an ion with a +2 charge?

Chemistry
2 answers:
Harrizon [31]3 years ago
8 0

Answer:

The correct answer to this is Mg.

Explanation:

Mg is the second element at the Periodic Table, down Be. As its the oxidation number is 2, it can release two electrons to form compounds. Not like C that is tetravalent, or Na that is a monovalent element (1e-). Si, as C has 4 oxidation states, and phosphorus can lose or get 3 e- (for example PCl3), also get 5e- (for example  P2O5)

julsineya [31]3 years ago
7 0

Answer:

Mg

Explanation:

Magnesium has a valency of +2

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Exactly how much time must elapse before 16 grams of potassium-42decays, leaving 2 grams of the original isotope?(1) 8 × 12.4 ho
AleksandrR [38]
The answer is <span>(3) 3 × 12.4 hours
</span>
To calculate this, we will use two equations:
(1/2) ^{n} =x
t_{1/2} = \frac{t}{n}
where:
<span>n - number of half-lives
</span>x - remained amount of the sample, in decimals
<span>t_{1/2} - half-life length
</span>t - total time elapsed.

First, we have to calculate x and n. x is <span>remained amount of the sample, so if at the beginning were 16 grams of potassium-42, and now it remained 2 grams, then x is:
2 grams : x % = 16 grams : 100 %
x = 2 grams </span>× 100 percent ÷ 16 grams
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Thus:
<span>(1/2) ^{n} =x
</span>(0.5) ^{n} =0.125
n*log(0.5)=log(0.125)
n= \frac{log(0.5)}{log(0.125)}
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It is known that the half-life of potassium-42 is 12.36 ≈ 12.4 hours.
Thus:
<span>t_{1/2} = 12.4
</span><span>t_{1/2} *n = t
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Therefore, it must elapse 3 × 12.4 hours <span>before 16 grams of potassium-42 decays, leaving 2 grams of the original isotope</span>
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