2SO2 + O2 ------> 2SO3
1) M(SO2)= 32.0 + 2*16.0 = 64 g/mol
2) 100.0 g SO2 * 1 mol SO2/64 g SO2 = 1.5625 mol SO2
3) 2SO2 + O2 ------> 2SO3
2 mol 1 mol
1.5625 mol x mol
x= 1.5625/2=0.78125 ≈ 0.7813 mol O2
Answer: 0.7813 mol O2.
Answer:
Total Ionic equation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
Explanation:
Chemical equation:
H₂O₂(aq) + MgSO₃(aq) → MgSO₄(aq) + H₂O(l)
Balanced chemical equation:
H₂O₂(aq) + MgSO₃(aq) → MgSO₄(aq) + H₂O(l)
Total Ionic equation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
Water can not split into ions because it is present is liquid form.
Answer:
BARIUM HYDROXIDE IS THE COMPOUND
The atomic number is the total number of protons in the nucleus. The mass number is the total number of particles in the nucleus. That includes the neutrons and the protons. So, the atomic number is 31. When you look at the element on the periodic table with a designated atomic number of 31, that would be Gallium, with a symbol of Ga. Mass number is 31 + 36 = 67. So, the answer is A.
Oxid # : 0 0 +2 -1

∴ the nickel was oxidized while chlorine was reduced
nickel reduction potential = - 0.25 V
but since it is being oxidised the you have to switch the integer sign so the
the potential of nickel in this case becomes + 0.25 V
chlorine was reduced thus its reduction potential remains same = + 1.36 V
Overall Cell potential = ∑ of half cell potential
The overall cell potential = (+ 1.36) + (+ 0.25)
= + 1.61 V
∴
the answer would be D