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dexar [7]
3 years ago
13

Why does the water turn blue after some time when blue ink is dropped in water? Which property

Chemistry
1 answer:
zepelin [54]3 years ago
7 0

Answer:

Particles are constatantly moving and diffusing

This is possible because of diffusion

Explanation:

Hope this helps

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Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
Mention two factors which affect pressure due to liquid contained in a vessel​
sveticcg [70]

Answer:

depth of the liquid and nature of liquid affects the pressure due to liquid contained in a vessel

3 0
2 years ago
Read 2 more answers
Calculate the new pressure of a gas if the gas at 50 ˚C and 81.0 kPa is heated to 100 ˚C at a constant volume.
Debora [2.8K]

Answer:

93.5 kPa

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 81.0 kPa
  • Initial temperature (T₁): 50 °C
  • Final pressure (P₂): ?
  • Final volume (T₂): 100 °C

Step 2: Convert the temperatures to the Kelvin scale

When working with gases, we need to consider the absolute temperature. We will convert from Celsius to Kelvin using the following expression.

K = °C + 273.15

T₁: K = 50°C + 273.15 = 323 K

T₂: K = 100°C + 275.15 = 373 K

Step 3: Calculate the final pressure of the gas

At a constant volume, we can calculate the final pressure of the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 81.0 kPa × 373 K/323 K

P₂ = 93.5 kPa

7 0
3 years ago
In the reaction
user100 [1]

Answer:

a) KOH

Explanation:

In the given balanced reaction

                         2K + 2H2O → 2KOH + H2

In the compound KOH,

The elements are K,O, and H and in the compound, there is one mole each of K , O ,and H.

So the element ratio here is 1 : 1 : 1.

7 0
3 years ago
Read 2 more answers
why was the mass lost when the reaction was done in the normal setup but stayed the same when it was done in the gas collection
german
<h2>Answer : Law of conservation of mass</h2><h3>Explanation :</h3>

The law of conservation of mass states that in any reaction mass is neither created nor lost it has to remain constant in a system.

In this case, when the reaction setup was done in normal way the mass was  lost in surrounding was not considered nor being calculated; whereas when the reaction was studied in a closed system where the gas was collected after the reaction the mass changes was noted down which helped to prove the point of law of conservation of mass and energy.

One can consider an example of soda can where the carbonated drink contains pressurized carbon dioxide gas. when opened the gas bubbles gets lost into the surroundings and we don't measure the mass changes. Instead if the soda can was opened in such a way where the gas evolved was measured then the mass changed would remain the same.

6 0
3 years ago
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