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Artist 52 [7]
4 years ago
7

How many total electrons are shared between two nitrogen atoms when they bond to form a diatomic nitrogen molecule?

Chemistry
1 answer:
GuDViN [60]4 years ago
8 0

Explanation:

Diatomic Nitrogen molecule means the two atoms of nitrogen N_{2}.

  • A single nitrogen contains 5 electrons in its valence shell which has 3 single electrons and one pair of electron. When the bond is being made the three single electrons makes the covalent bond with the 3 electrons of other atom which results in 3 pairs . The total electrons shared between the atoms are 3 pairs  (6 electrons) . while when it completes the octate the N_{2} is formed.
  • Nitrogen is colorless, odorless, tasteless and the inert diatomic gas.Nitrogen combines of near about 78% of Earth's atmosphere.It is non-flammable which does not support combustion , it occurs in all living organisms. Nitrogen is used in most of the Biological processes  and also used in the formation of fertilizers, in the form of ammonia and ammonia based compounds.It is also used in Chemical Industries for making nylon , explosives, dyes and etc. The breathing of Nitrogen is deadly, as it displaces the oxygen.
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What is the pressure of a gas if the volume is 96.2 L, the temperature is 25°C and there are 1.24 moles?
galben [10]

Answer:

0.315 atm

Explanation:

PV = nRT

P(96.2) = (1.24)(0.08206)(25 + 273)

P = 0.315 atm

6 0
3 years ago
A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h
NikAS [45]

Nitrogen combine with hydrogen to produce ammonia \text{NH}_3 at a 1:3:2 ratio:

\text{N}_2 \; (g) + 3 \;  \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. 3 \; \text{mol} of hydrogen gas would have been consumed while 2 \; \text{mol} of ammonia would have been produced. The final mixture would therefore contain

  • 17 \; \text{mol} of \text{H}_2 \; (g) and
  • 2 \; \text{mol} of \text{NH}_3 \; (g)

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

  • \begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.926 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.723 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  2.037 \times 10^{2} \; \text{kPa} \end{array}
6 0
3 years ago
Show the curved-arrow mechanism for the Claisen condensation of ethyl ethanoate treated with ethoxide ion. Include all formal ch
Anna [14]

Answer:

See explaination

Explanation:

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4 0
3 years ago
Which of the following information can be determined from this isotope: sodium 23 and why?
JulsSmile [24]

<h2>YOUR ANSWER Is number of istopes</h2>

✌️

4 0
3 years ago
A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p
hichkok12 [17]

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
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Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

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P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

  • Total pressure = P₂He + P₂Ar = 733 torr
4 0
3 years ago
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