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4 years ago

Natalie purchased a used car for $12, 200 and had to pay 83 % sales tax. How much tax did she pay?

Mathematics

1 answer:

Fynjy0 [20]4 years ago

3 0

Answer:

$5,533.33

Step-by-step explanation:

83% sales tax seems a lot, but ok.. anyway...i'm assuming that this is correct.

the final amount that she paid is made up of 2 parts:

100% of the car's price (list price of the car) + 83% of the cars price in taxes

if we add these together, that means she paid

100% + 83% = 183% of the car's price. We are told that this number is $12,200

hence,

183% --------> represents $12,200

1% ------------> represents $(12,200 ÷ 183)

amount in taxes = 83% -------> represents $(12,200 ÷ 183) x 83 = $5,533.33

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

3 years ago

An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s

aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).

Step-by-step explanation: Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

$\textup{d}=20~\textup{cm}.$

So, the radius of the circular cross-section will be

$\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.$

Therefore, cross-sectional area of the pipe is

$\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.$

Thus, the answer is 314.28 cm² (approx.).

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4 years ago

In a survey of 300 house wires. It was discovered

ruslelena [56]

Answer:

46 housewives read all three magazines.

Step-by-step explanation:

Given:

n(A) = 150

n(B) = 200

n(C) = 156

n(A∩B) = 48

n(B∩C) = 60

n(A∩C) = 52

n(A∪B∪C) = 300

so we know the relation as:

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) + n(A∩B∩C)

∴ n(A∩B∩C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(A∩C) - n(A∪B∪C)

= 150 + 200+ 156 - 48 - 60 - 52 - 300

= 46

Hence the number of housewives that had read all three magazine is 46.

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3 years ago