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DochEvi [55]
2 years ago
11

ABCD is a quadrilateral inscribed in a circle, as shown below:

Mathematics
1 answer:
Virty [35]2 years ago
3 0

The sum of the angles ∠B and ∠D will be 180°. Then the correct option is A.

<h3>What is a cyclic quadrilateral?</h3>

If the quadrilateral is inscribed in a circle then the quadrilateral is known as a cyclic quadrilateral.

Circle O is shown with a quadrilateral ABCD inscribed inside it.

Angle A is labeled x + 16.

Angle B is labeled x.

Angle C is labeled 6x - 4.

Angle D is labeled 2x + 16.

We know that the sum of the opposite angles of the cyclic quadrilateral is 180 degrees. Then we have

Then the sum of the angles ∠A and ∠C will be 180°.

              ∠A + ∠C = 180°

(x + 16)° + (6x - 4)° = 180°

Then the sum of the angles ∠B and ∠D will be 180°.

        ∠B + ∠D = 180°

(x)° + (2x + 16)° = 180°

Thus, the correct option is A.

More about the cyclic quadrilateral link is given below.

brainly.com/question/15061291

#SPJ1

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Step-by-step explanation:

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3 years ago
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5. Solve the following triangle for all missing sides and angles.
Ipatiy [6.2K]

Answer:

Part I : 100°

Part II : a = 29.2

Part III : b = 20.95

Step-by-step explanation:

See the attached diagram of the triangle.

Part I: ∠ A = 180° - ∠ B - ∠ C = 180° - 45° - 35° = 100°

Part II: Now, applying the law of sines, we have

\frac{AB}{\sin 35^\circ} = \frac{BC}{\sin 100^\circ}

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⇒ a = \frac{17}{\sin 35^\circ} \times \sin 100^\circ

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Part III: Now, applying law of cosine, we have  

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I need an answer for part A and B plz
Sladkaya [172]

Answer:

Part A: 4 cups

Part B: 5 fluid ounces

Step-by-step explanation:

Part A: Since the ratio of vinegar to water is 1:16, 1 cup of vinegar is 16 cups of water. Divide both by 4 to get 1/4 cups of vinegar to 4 cups of water.

PartB: Since we have 80 fluid ounces of water, and 16 is 16 times 1, 80/16 is 5 fluid ounces.

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4 years ago
Let Bold u comma Bold v comma Bold w 1 comma Bold w 2 comma and Bold w 3 be vectors in Bold Upper R Superscript n. If u and v ca
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Answer:

Step-by-step explanation:

given that U, V are two vectors in R^n

These two vectors can be written as a linear combination of 3 vectors

w1, w2, and w3

To prove that  U+V also can be written as a linear combination of these three vectors.

Since U is a linear combination we can write for not all a,b, c equal to 0

U = aw1+bw2+cw3

Similarly for d,e,f not all equal to 0

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Adding these we have

U+V =(a+d)w1 + (b+e) w2+(c+f)w3

Here all a+d, b+e or c+f cannot be simultaneously 0.

So we get U+V can be written as a linear combination of w1, w2 w3 as follows:

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