Answer:
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).
Step-by-step explanation:
For any value of x g(x) is always greater than h(x) and for any value of x, h(x) will always be greater than g(x) are not true.
The given function is:
g(x) = x^2 and h(x) = –x^2
x=0
g(0)=(0)^2 = 0
h(0)= -(0)^2 = 0
Now check the condition for x = -1
put x =-1 in the given functions.
g(x)=x^2
g(-1) = (-1)^2 = 1
h(x)= -x^2
h(-1) = -(-1)^2 = -1
g(x)>h(x)
Now take a positive value of x= 3
Put the value in the given functions:
g(3) = (3)^2 = 9
h(3) = -(3)^2 = -9
g(x)>h(x)
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x)....
