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3 years ago

If -5x-y=1 is a true equation, what would be the value of 5(-5x-y)?

Mathematics

1 answer:

Tanzania [10]3 years ago

7 0

Answer:

-25-5x-5y

Step-by-step explanation:

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Hannah and Anthony are siblings who have ages that are consecutive odd integers. The sum of their ages is 92. Which equations co

Wewaii [24]

Answer:

h = Hannah's age

h - 2 = Anthony's age

Hannah is 47, Anthony is 45

Step-by-step explanation:

Using one variable and an expression with the same variable, you can find the sum of the siblings ages:

h = Hannah's age

h - 2 = Anthony's age

h + (h - 2) = 92

Combine like terms: 2h - 2 = 92

Add '2' to both sides: 2h - 2 + 2 = 92 + 2 or 2h = 94

Divide by 2: 2h/2 = 94/2

Solve for h: h = 47 years old (Hannah)

h - 2 = 45 years old (Anthony)

6 0

3 years ago

Block of bags with 2 squares, 5 circles, 2 triangles and 4 rectangles. What fraction are squares?

Advocard [28]

Answer:

2/13

Step-by-step explanation:

There are thirteen shapes and out of that two are

3 0

3 years ago

Find the measure(s) of the interior angles of the polygon.

professor190 [17]

Answer:

X = 57

3x-6 = 165

Step-by-step explanation:

Udbzkejdnkdjfif

6 0

2 years ago

Meredith

victus00 [196]

Answer:

Step-by-step explanation:

Because in the number 15.8, it is equal to 15.80. 80 is more than 17.

5 0

2 years ago

A committee that consists of five members are to be chosen from 6 boys and 5 girls. Find the number of different committees that

Daniel [21]

Answer:

281 different committees can be formed if the number of boys is more than the number of girls.

Step-by-step explanation:

The order in which the people are chosen to the committee is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Number of boys more than the number of girls:

3, 4 or 5 boys.

3 boys:

3 boys from a set of 6.

2 girls from a set of 5. So

$C_{6,3}C_{5,2} = \frac{6!}{3!3!} \times \frac{5!}{2!3!} = 200$

4 boys:

4 boys from a set of 6.

1 girl from a set of 5. So

$C_{6,4}C_{5,1} = \frac{6!}{4!2!} \times \frac{5!}{1!4!} = 75$

5 boys:

5 boys from a set of 6. So

$C_{6,5} = \frac{6!}{5!1!} = 6$

Total:

200 + 75 + 6 = 281

281 different committees can be formed if the number of boys is more than the number of girls.

5 0

2 years ago