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soldi70 [24.7K]
3 years ago
9

A line crosses the coordinates (-3, 5) and (4, -2). What is the slope-intercept form of the equation of this line?

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-2-5}{4-(-3)}\implies \cfrac{-7}{4+3}\implies \cfrac{-7}{7}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=1[x-(-3)]\implies y-5=1(x+3) \\\\\\ y-5=x + 3\implies y=x+8

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9/10

Step-by-step explanation:

You can write 9 as the numerator (top number), and 10 as the denominator (bottom number), and that will be equivalent to 0.9

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Step-by-step explanation:

Given that P varies directly as I then the equation relating thenm is

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4 years ago
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Step-by-step explanation:

12 -4x-5x = 39

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AnnyKZ [126]

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This sequence be represented as a recursive equation by a1=8 and an=2a1

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