Answer:
21.81grams
Explanation:
According to the question, an agar medium requires the following ingredients: 21 grams (g) of
agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters (mL) of distilled water.
Hence, the dry ingredient contain 21grams (g) of agar, 500milligrams (mg) of dextrose, 3decigrams (dg) of Sodium, and 1centigrams (cg) of pottasium.
We need to convert all units (not in grams (g)) to grams.
1grams = 1000milligrams
500 milligrams = 500/1000
= 0.500grams.
1grams = 10decigrams
3decigrams = 3/10
= 0.3grams
1grams = 100centigrams
1centigrams = 1/100
= 0.01 grams
Therefore, we have 21g, 0.500g, 0.3g, and 0.01g
The total dry weight of the ingredients will be:
21 + 0.500 + 0.3 + 0.01
= 21.81grams
