Question

A lab technician is preparing agar medium. The medium requires 21 grams (g) of

Answer 1

Answer:

21.81grams

Explanation:

According to the question, an agar medium requires the following ingredients: 21 grams (g) of

agar, 500 mg of dextrose, 3 dg of sodium, and 1 cg of potassium per 1,000 milliliters (mL) of distilled water.

Hence, the dry ingredient contain 21grams (g) of agar, 500milligrams (mg) of dextrose, 3decigrams (dg) of Sodium, and 1centigrams (cg) of pottasium.

We need to convert all units (not in grams (g)) to grams.

1grams = 1000milligrams

500 milligrams = 500/1000

= 0.500grams.

1grams = 10decigrams

3decigrams = 3/10

= 0.3grams

1grams = 100centigrams

1centigrams = 1/100

= 0.01 grams

Therefore, we have 21g, 0.500g, 0.3g, and 0.01g

The total dry weight of the ingredients will be:

21 + 0.500 + 0.3 + 0.01

= 21.81grams