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erma4kov [3.2K]

3 years ago

5

Wendy bought 3.743.74 pounds of swiss cheese at $6.29$6.29 per pound and 1.341.34 pounds of provolone cheese at $6.29$6.29 per p

ound. Which expression does NOT show the total cost, in dollars, of her purchase?

1 answer:

lyudmila [28]3 years ago

5 0

6.29 ⋅ 3.74 + 1.<span>34

all i did was guess but i got it right. TTM right? That is what most of these questions are from </span>

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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

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Plant 2: follow the points that touch the x and y intersections (my teacher calls them "pretty points"). You see that the slope is 1, because it's going up and right by 1, so 1/1.

Although the measurements are wrong, the statment is true, because 3>1.

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