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steposvetlana [31]
3 years ago
5

Given f(x) and g(x) = k•f(x), use the graph to determine the value of k

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0

Step-by-step explanation:

f(x) has a slope of 1.

g(x) has a slope of -5

so k must be -5 to change f(x)'s slope from 1 to -5

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A neighborhood development that is 4 acres is to be divided into 2/3 acre lots. How many lots can be created?
Brilliant_brown [7]

Answer:

6

Step-by-step explanation:

4 = 12/3

12/3 divided by 2/3 = 6

2/3

2/3

2/3

2/3

2/3

2/3

+

______

12/3

The answer is 6

7 0
3 years ago
1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both
Alja [10]

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}

8 0
3 years ago
5x 1/4= 61/4 help me please!
Vesnalui [34]
So basically 5 x 1/4 would equal 1 1/4 ( One, One Fourth )
3 0
3 years ago
MATCH THE TERM WITH THE STATEMENT!! PLEASE HELP!!!
Dvinal [7]
The first one is reflexive property
The second one is given
The third one is ASA
7 0
3 years ago
Which of the following functions are solutions of the differential equation y" + y = 7 sin(x)? (Select all that apply.)
Nikitich [7]

The homogeneous equation

y'' + y = 0

has characteristic equation

r² + 1 = 0

with roots at r = ± √(-1) = ± i, and so the characteristic solution is

y = C₁ cos(x) + C₂ sin(x)

Using the method of undetermined coefficients, suppose

y = a x cos(x) + b x sin(x)

(we would normally consider y = a cos(x) + b sin(x), but cos(x) and sin(x) are already part of the characteristic solution)

The derivatives are

y' = a cos(x) - a x sin(x) + b sin(x) + b x cos(x)

y' = (b - a x) sin(x) + (a + b x) cos(x)

and

y'' = -a sin(x) + (b - a x) cos(x) + b cos(x) - (a + b x) sin(x)

y'' = (-2a - b x) sin(x) + (2b - a x) cos(x)

Then

y'' + y = (-2a - b x) sin(x) + (2b - a x) cos(x) + a x cos(x) + b x sin(x)

7 sin(x) = -2a sin(x) + 2b cos(x)

and it follows that a = -7/2 and b = 0.

So, the general solution to the DE is

y = C₁ cos(x) + C₂ sin(x) - 7/2 x cos(x)

which means the only valid solutions from the given choices are

y = 7 sin(x)

y = 7 cos(x)

4 0
2 years ago
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