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fomenos
3 years ago
10

4|x+3|<8 i need help asap

Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0

Answer:

-5 <x<-1

Step-by-step explanation:

4|x+3|<8

Divide by 4

4|x+3| /4<8/4

|x+3|<2

There are two solutions one positive and one negative, remember to flip the inequality for the negative

x+3 <2    and x+3 >-2

Subtract 3 from each side

x+3-3 <2-3   and x+3-3 >-2-3

x<-1   and x>-5

-5 <x<-1

Elena-2011 [213]3 years ago
3 0

Answer:

4|x+3|>=8. This deals with absolute value inequalities. Overview; Steps; Topics Terms and topics; Links Related links; 2 solution(s) found. x>=-1. x<=-5. See steps. Step by …

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zheka24 [161]

Answer:

Anne is the best hitter as she has the best hitting average of 0.406

Step-by-step explanation:

Anne hits 65 bases out of 160 at - bats.

Beth's betting average = 0.399

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Now, we need to convert all the three hitting rates into same parameters to compare them with each other.

Average hit rate of Anne = \frac{\textrm{Total numberof base}}{\textrm{Total number of  at - bats}}

= \frac{65}{160}  = 0.406

⇒The betting average of Anne = 0.406

Now, The hit - rate of Collin = 40%

Converting the percentage rate into decimal, we get the hit rate of Collin

= \frac{40}{100}  = 0.40

Hence, we get that Hitting Average of :

<u>Anne = 0.406</u>,  Beth = 0.3999 and Collin = 0.400

Hence, from the above data Anne is the best hitter as she has the best hitting average of 0.406.

6 0
3 years ago
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EastWind [94]

Answer:

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Step-by-step explanation:

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Answer:

Hi hopefully this helps you!

Step-by-step explanation:

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A = π(1.5)^2

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Because this is a semicircle, divide this area by 2

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\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

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➺\: 4 + 3 \: ( \: 10 - 2 \times 2 \times 2 \: )

➺\: 4 + 3 \: ( \: 10 - 8 \: )

➺\: 4 + 3 \: ( \: 2 \: )

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➺\: 10

<h3><u>Note</u>:-</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

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