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fomenos
3 years ago
10

4|x+3|<8 i need help asap

Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0

Answer:

-5 <x<-1

Step-by-step explanation:

4|x+3|<8

Divide by 4

4|x+3| /4<8/4

|x+3|<2

There are two solutions one positive and one negative, remember to flip the inequality for the negative

x+3 <2    and x+3 >-2

Subtract 3 from each side

x+3-3 <2-3   and x+3-3 >-2-3

x<-1   and x>-5

-5 <x<-1

Elena-2011 [213]3 years ago
3 0

Answer:

4|x+3|>=8. This deals with absolute value inequalities. Overview; Steps; Topics Terms and topics; Links Related links; 2 solution(s) found. x>=-1. x<=-5. See steps. Step by …

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Check picture if u kno geometry
Scorpion4ik [409]

Answer:

141.5 in

Step-by-step explanation

AB // CD // EF

12 / 15 = 21 / y        (By the property of 3 parallel lines and its transversals)

y = (15*21) / 12 = 26.25

CD // EF // GH

21 / y = x / 10       21 / 26.25 = x / 10

x = (21*10) / 26.25

x = 8

perimeter of ABHG = (y-14) +15 + y + 10 + (5x-3) + x + 21 + 12 = 141.5

                               

4 0
3 years ago
How is 3/8 written as an decimal?
yaroslaw [1]
3/8 written as an decimal is <span>0.375</span>
8 0
3 years ago
I just need to know what is m=
natali 33 [55]

Answer:

- 2

Step-by-step explanation:

Given :

Point A = (-1, 4)

Point B = (1, 0)

x2 = - 1 ; y2 = 4 ; x1 = 1 ; y1 = 0

Rise = (y2 - y1) = 4 - 0 = 4

Run = (x2 - x1). = - 1 - 1 = - 2

Slope = Rise / Run = 4 / - 2 = - 2

The slope, m = - 2

5 0
3 years ago
The following diagram models a ratio relationship.
kakasveta [241]

Answer:

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6 0
3 years ago
Read 2 more answers
two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)
nadya68 [22]

Answer:

24\sqrt{5}\ yards

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}

So side of one square is 5\sqrt{5}

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

=4*5\sqrt{5} \\=20\sqrt{5}

For second square:

A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}

The perimeter will be:

P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}

So the total fence will be: P1+P2

= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards

3 0
3 years ago
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