Hope this helps. :D
(Please mark as brainliest thanks)
Here you go! I hope I can get brainliest!
Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
Answer:
y^3+27
Step-by-step explanation:
*use box method
Answer:
d = 0.0175n ---> required equation
Billy can buy 285.714 gram nut with $5
Step-by-step explanation:
cost of 100g loose nut = $1.75
dividing LHS and RHS by 100
cost of 100/100g loose nut = $1.75
Thus, cost of 1 gm loose nut = $0.0175
let the weight of loose nut be n gm
Multiplying LHS and RHS by n
cost of x g loose nut = $0.0175*n = $0.0175n
It is given that Billy spent d dollars to buy n gm nuts
thus,
d = 0.0175n ---> required equation
________________________________________________
He spent $5 to buy nuts
substituting value of d as 5 we have
0.0175n = 5
=>n = 5/0.0175 = 285.714
Thus, Billy can buy 285.714 gram nut with $5.
