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2 years ago

I need help with this question.

Mathematics

1 answer:

Papessa [141]2 years ago

5 0

Answer:

It's A, c =2.5d

Step-by-step explanation:

When it comes to problems like this, I usually look through the answers and try to plug in the numbers until I get the right equation that fits with the graph.

2.5(5) = 12.5

2.5(10)= 25

2.5(15)= 37.5

2.5(20) = 50

2.5(25) = 62.5

If you compare this to the graph, you'll notice the solutions are the same as the Total Cost (c). That's because c= 2.5d is the right equation for this graph. (Sorry if my explanation is confusing)

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Pls help im confused D:

Murljashka [212]

Answer:

B is your answer

Step-by-step explanation:

5 0

2 years ago

Can any one here please help me in this math problem I really need help

MArishka [77]

Answer:

The volume of the solid is the volume of the prism minus the volume of the cylinder.

For the cylinder, diameter = d = 4 cm

radius = d/2 = (4 cm)/2 = 2 cm

V = volume of prism - volume of cylinder

The volume of a prism is length times width times height.

The volume of a cylinder is pi times the square of the radius times the height.

V = LWH - (pi)r^2h

V = 6 cm * 6 cm * 15 cm - (pi)(2 cm)^2(15 cm)

V = 540 cm^3 - 60pi cm^3

V = (540 - 60pi) cm^3

5 0

2 years ago

To convert centimeters to inches, we multiply the measurement in centimeters by 2.54. Identify the type of relation between cent

miskamm [114]

The relationship between centimeters and inches is linear. The equation in the relationship is:

y= 2.54x , with x as inches and y as centimeters.

The graph for this equation results to a straight line. This equation has a degree of one.

5 0

3 years ago

State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should

Yuki888 [10]

Solving for Angles

$\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A$

* Do not forget to use the inverse function towards the end, or elce you will throw your answer off!

Solving for Edges

$\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2$

You would use this law under two conditions:

One angle and two edges defined, while trying to solve for the third edge
ALL three edges defined

* Just make sure to use the inverse function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under three conditions:

Two angles and one edge defined, while trying to solve for the second edge
One angle and two edges defined, while trying to solve for the second angle
ALL three angles defined [of which does not occur very often, but it all refers back to the first bullet]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0

2 years ago

By which transformation can the set representing the inverse of a function be found?

Marina CMI [18]

Answer:

C. reflection about the line y = x

Step-by-step explanation:

C. reflection about the line y = x

4 0

3 years ago