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vlabodo [156]
4 years ago
12

A graph has average temperature (degrees Fahrenheit) on the x-axis, from 0 to 60, and total coat sales on the y-axis, from 0 to

100. Which temperature values would an interpolation be limited to? less than 0 between 0 and 60 between 20 and 80 greater than 55
Mathematics
2 answers:
zzz [600]4 years ago
8 0

Answer:

3 and 60

Step-by-step explanation:

Georgia [21]4 years ago
3 0

Answer:

0 and 60

Step-by-step explanation:

your welcome

edge 2020

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1/3 = ?/9 what is the answer
Wittaler [7]
It would be 3/9 because 3x3 is 9 and what u do to the denominator you have to do to the numerator, 1x3 is 3, so the answer is 3/9
8 0
4 years ago
Read 2 more answers
What is the center and radius of -10x = -121 - y2 - x2 -22y
OlgaM077 [116]

We need to find the center and the radius of

-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y

The general circle equation is the following

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center and

r is the radius

1. rearrange the equation

(x^2-10x)+(y^2+22y+121)=0

2. Add 25 on both sides

(x^2-10x+25)+(y^2+22y+121)=25

3. Factor

(x-5)^2+(y+11)^2=5^2

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

8 0
1 year ago
Whats the slope of this graph​
AleksAgata [21]
The answer is 3/2 rise over run
5 0
4 years ago
Which formula can be used to describe the sequence below? <br> 29, 9, 3, 1, 1/3,.....
Maksim231197 [3]

Answer:

Answer is   3^{4-n}

Step-by-step explanation:

It is 29 in place of 27 . and Its a geometric series with first term 27 and common ratio \frac{1}{3}

and  general formula for  given sequence is given by  a (r)^{n-1}

so plugging the value of a and r ,we get

   27 ([tex]\frac{1}{3})^{n-1}[/tex]

   3^3(\frac{1}{3} )}^{n-1}

      3^{4-n}

5 0
4 years ago
The random variable K has a geometric distribution with mean 16. Which of the following is closest to the standard deviation of
sdas [7]

Answer: d. 15.49

Step-by-step explanation:

Given : The random variable K has a geometric distribution with mean 16.

Formula for Mean and standard deviation in geometric distribution:

\mu=\dfrac{1}{p}    (1)

\sigma=\dfrac{\sqrt{1-p}}{p}   (2), where p is the probability of success in each trial.

Since \mu=16  (Given)

Then from (1) ,

\dfrac{1}{p}=16\\\Rightarrow\ p=\dfrac{1}{16}=0.0625

Put value of p in (2),

\sigma=\dfrac{\sqrt{1-0.0625}}{0.0625}=\dfrac{\sqrt{0.9375}}{0.0625}  

=\dfrac{0.968245836552}{0.0625}

=15.4919333848\approx15.49

Hence, the standard deviation of random variable K is closest to 15.49.

Therefore , the correct answer is d. 15.49 .

6 0
3 years ago
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