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djyliett [7]
1 year ago
10

What is the center and radius of -10x = -121 - y2 - x2 -22y

Mathematics
1 answer:
OlgaM077 [116]1 year ago
8 0

We need to find the center and the radius of

-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y

The general circle equation is the following

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center and

r is the radius

1. rearrange the equation

(x^2-10x)+(y^2+22y+121)=0

2. Add 25 on both sides

(x^2-10x+25)+(y^2+22y+121)=25

3. Factor

(x-5)^2+(y+11)^2=5^2

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

x + 2y = 8 -----------(I)

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Add equation (I) & (II) and thus y will be eliminated and we can get the value of 'x'

(I)           x + 2y = 8

(II)          <u>x - 2y  = -4</u><u>      </u>{Now add}

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