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Ilia_Sergeevich [38]
3 years ago
13

On ten acres of native forest there are eight white-tailed deer, seven coyotes, 45 armadillos, and 231 loblolly pine trees. Whic

h population has the highest density?
Question 12 options:

white-tailed deer

coyotes

armadillos

loblolly pine trees
Biology
1 answer:
Natasha2012 [34]3 years ago
5 0

loblolly pine trees

Explanation:

Population density refers to the amount of organisms living in a particular area:

            Population density = \frac{number of organisms}{Area}

Area of the forest = 10acres

Population densities of:

  White-tailed deer = \frac{8 white tailed deer}{10acres}

                                 = 0.8white tailed deer/acres

   Coyotes = \frac{7 coyotes}{10acres}= 0.7coyotes/acres

   Armadillos = \frac{45 armadillos}{10acres} = 4.5armadillos/acres

   loblolly pine = \frac{231loblolly pine trees}{10acres} = 23.1loblolly pine trees/acre

The population with the highest density is that of the loblolly pine trees with 23.1 of the trees in an acre.

learn more;

Population brainly.com/question/13181732

#learnwithBrainly

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