On ten acres of native forest there are eight white-tailed deer, seven coyotes, 45 armadillos, and 231 loblolly pine trees. Whic

Question

3 years ago

13

h population has the highest density?
Question 12 options:

white-tailed deer

coyotes

armadillos

loblolly pine trees

1 answer:

Natasha2012 [34] · Answer 1 · 2022-07-09T19:30:33+03:00

loblolly pine trees

Explanation:

Population density refers to the amount of organisms living in a particular area:

Population density = $\frac{number of organisms}{Area}$

Area of the forest = 10acres

Population densities of:

White-tailed deer = $\frac{8 white tailed deer}{10acres}$

= 0.8white tailed deer/acres

Coyotes = $\frac{7 coyotes}{10acres}$ = 0.7coyotes/acres

Armadillos = $\frac{45 armadillos}{10acres}$ = 4.5armadillos/acres

loblolly pine = $\frac{231loblolly pine trees}{10acres}$ = 23.1loblolly pine trees/acre

The population with the highest density is that of the loblolly pine trees with 23.1 of the trees in an acre.

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