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3 years ago

What are the domain and the range of this relation?

Mathematics

2 answers:

iVinArrow [24]3 years ago

8 0

Answer:

Domain: {-5, 3, 4}

Range: {-2, 3, 4}

Step-by-step explanation:

Domain: set of all inputs

{-5, 3, 4}

Range: set of all outputs

{-2, 3, 4}

daser333 [38]3 years ago

6 0

Answer:

Domain:{-5,3,4} ; Range: {-2,3,4}

Step-by-step explanation:

Domain= value x

Range= value y

x | y

-5,4

3, -2

3, 4

4, 3

When finding the relations you do not have to repeat the numbers.

Domain:{-5,3,4} ; Range: {-2,3,4}

Hope this helped :)

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Find ∂f ∂x , ∂f ∂y , and ∂f ∂z . f(x, y, z) = 32xyz

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Step-by-step explanation:

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3 years ago

The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

pshichka [43]

Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi x^{3}$

For larger sphere: $Radius = 2x$

$Volume \ of \ sphere = \frac{4}{3} \pi r^{3}$

$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$