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Verdich [7]
3 years ago
8

A box contains 87 coins, only Dimes and nickels. The amount of money I the box is $5.45. How many dimes and how many nickels are

in the box?
Mathematics
2 answers:
Tamiku [17]3 years ago
5 0
There are 65 nickels and 22 dimes in the box.
Slav-nsk [51]3 years ago
3 0
Write the situation as a simultaneous eqution: 
x+y=87
10x+5y=545

Now solve for y by multiplying the whole of the first equation by the coefficient of x:
10x+10y=870
10x+5y=545

5y=325
y=65 nickels in the box
x+y=87
x=22 dimes in the box
To prove this is correct, we do (10 x 22)+(5 x 65)=545 cents ($5.45)
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Im not too sure with these, but this is what i got

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4 0
3 years ago
What is the solution of the system of equations c + 4d = 8 and c = 4d - 6
Tema [17]
Rewrite the second equation in same form as the first So we have

c + 4d = 8

c - 4d = -6     Now add:-

2c + 0 = 2
2c = 2

c = 1  

Now substitute c = 1 in the first equation:-

1 + 4d = 8
4d = 7

d =  7/4  = 1 3/4

Answer c = 1 and d = 1 3/4  Answer
3 0
3 years ago
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2x^2 - 3x^2 - 4 + 6. pls Help Me ASAP .
Allisa [31]
2x^2-3x^2-4+6
Subtract the base
x^2+2
3 0
2 years ago
A science teacher ordered $1848 worth of microscopes and dissection kits for the new science lab. A total of 30 microscopes and
andrezito [222]

Answer:

Microscopes cost $44 and Dissection Kits cost $11

Step-by-step explanation:

Using the information given, we can make the system of equations:

30x+48y=1848

x represents the price of microscopes and y represents the price of dissection kits.

We also know that microscopes will be 4x the price of dissection kits. Therefor:

x=4y

We can plug these two equations together to find the answer.

30(4y)+48y=1848

120y+48y=1848

168y=1848

y=11

Using the y-value, can find the x-value.

x=4(11)

x=44

4 0
3 years ago
AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS
Blababa [14]

Answer:

P(A\textrm{ and }B)=\frac{3}{14}

Step-by-step explanation:

Given:

P(A)=\frac{4}{7}

P(B|A)=\frac{3}{8}

We know that, conditional probability of B given that A has occurred is given as:

P(B|A)=\frac{P(A\cap B}{P(A)}. Expressing this in terms of P(A\cap B), we get

P(A\cap B)=P(B|A)\times P(A)

Plug in the known values and solve for P(A\cap B). This gives,

P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}

Therefore, the probability of events A and B occurring is \frac{3}{14}.

6 0
3 years ago
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