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Verdich [7]
3 years ago
8

A box contains 87 coins, only Dimes and nickels. The amount of money I the box is $5.45. How many dimes and how many nickels are

in the box?
Mathematics
2 answers:
Tamiku [17]3 years ago
5 0
There are 65 nickels and 22 dimes in the box.
Slav-nsk [51]3 years ago
3 0
Write the situation as a simultaneous eqution: 
x+y=87
10x+5y=545

Now solve for y by multiplying the whole of the first equation by the coefficient of x:
10x+10y=870
10x+5y=545

5y=325
y=65 nickels in the box
x+y=87
x=22 dimes in the box
To prove this is correct, we do (10 x 22)+(5 x 65)=545 cents ($5.45)
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