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3 years ago

Find the domains of the following expressions: 5/the square root of 5-5x

Mathematics

1 answer:

AleksandrR [38]3 years ago

7 0

Interval notation

(-infinity sign, 1)

Set-builder notation

{x|x less than equal to 1}

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What is the simplest form of 1764

vova2212 [387]

Answer:

Step-by-step explanation:

Do the math:)

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3 years ago

Two rectangles are similar. If the height of the first rectangle is 3 inches, and the height of the second rectangle is 9 inches

Mrac [35]

The answer is B.) 3

I hope this helped!

8 0

3 years ago

Read 2 more answers

X+9=2x-3 FIND THE X!!!!!!

Ierofanga [76]

Answer:

x = 12

Step-by-step explanation:

To find "x", we need to isolate it. This means move "x" to the left side, and everything else to the right side.

When moving a number, do its reverse operation to the entire equation.

x + 9 = 2x - 3

x - 2x + 9 = 2x - 2x - 3 Subtract 2x from both sides

-x + 9 = -3

-x + 9 - 9 = -3 - 9 Subtract 9 from both sides

-x = -12

-x/-1 = -12/-1 Divide both sides by -1 to get rid of the negatives

x = 12 Final answer

Check your answer. Split the equation for the left and right sides. Substitute "x" for the answer "12".

LS: (left side)

x + 9

= 12 + 9 Add

= 21

RS: (right side)

2x - 3

= 2(12) - 3 Multiply before subtracting

= 24 - 3 Subtract

= 21

Both sides equal to 21 when "x" is 12.

LS = RS left side equals right side

Therefore the answer is correct.

3 0

3 years ago

When Miguel babysits, he charges $7 per hour in addition to a fee of $9.

artcher [175]

Y=7x+9 here’s your answer

5 0

3 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

3 0

3 years ago