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Yakvenalex [24]
2 years ago
5

If 2 over 5 of a ton of concrete covers 5 over 6 of a wall, how many tons of concrete are required to cover the entire wall?

Mathematics
1 answer:
densk [106]2 years ago
6 0
Set up a proportion and use the cross multiply method to solve for x.
2/5 divided by 5/6 =x
2/5 divided by 5/6 is equal to 2/5 times 6/5
x=12/25 ton
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Use the quadratic formula to solve x^2-4x+3. Show your work. Then describe the solution
mars1129 [50]
Quadratic formula is x=(-b+-sqrt(b^2-4ac))/(2a)

a= 1, b=-4, and c=3

Therefore, x=(-(-4)+-sqrt((-4)^2-4(1)(3))/(2(1))

Solve for both the plus and minus equations; the answers will be the roots to the quadratic equation.
4 0
3 years ago
Can I plss have an answer on this i need it ASAP plss​
nordsb [41]

WHAT DOES THIS MEAN???... i needa think abt this one

4 0
2 years ago
NO LINKS OR FILES!
Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
On two investments totaling $11,500, Peter lost 3% on one and earned 4% on the other. If his net annual receipts were $⁢201, how
BlackZzzverrR [31]
Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
0.07Y = 546
Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
$201 = $201
6 0
3 years ago
A basketball team took a total of 100 shots. One player took 70% of all 100 shots, and
NemiM [27]

The player took a total of 70 shots and missed about 28 shots.

<h3>Percentage</h3>

Percentage is used in expressing a fraction number or decimal in fraction of 100. It is expressed using the '%' sign.

Given a total shot of 100, since the player took 70% of the shot, hence:

Total shot taken by the player = 70% of 100 = 0.7 * 100 = 70 shots.

Total shot shot missed = (100% - 60%) of 70 = 40% of 70 = 0.4 * 70 = 28 shots.

The player took a total of 70 shots and missed about 28 shots.

Find out more on Percentage at: brainly.com/question/24304697

4 0
2 years ago
Read 2 more answers
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