1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
allsm [11]
4 years ago
7

Computers from a particular company are found to last on average for 24 months without any hardware malfunction with a standard

deviation of 2 months. At least 100 ___ % of observations lie between 22 and 26 months?
Mathematics
1 answer:
vodomira [7]4 years ago
8 0

Answer:

At least 68% of observations lie between 22 and 26 months.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 24

Standard deviation = 2

22 = 24 - 2

22 is one standard deviation below the mean

26 = 24 + 2

26 is one standard deviation above the mean.

So, by the empirical rule, at least 68% of observations lie between 22 and 26 months.

You might be interested in
Help please .. im not good in math
olasank [31]
A ) acutely
B) obtuse
3 0
4 years ago
IMPORTANT I NEED HELP WITH THIS TEST QUESTION ITS DUE TODAY
Sunny_sXe [5.5K]

Answer:

2. square root 4841 and the answer is 69.5

3.     13.3km

4.   63.6

5.   470000

Step-by-step explanation:

My sister just did the test

4 0
4 years ago
A bagback that normally sales $39 is on sale for 30% off.Find the amount of the sale price
Ede4ka [16]
If the sale price is 30%, you turn that into a decimal and it will be .3. now you multiply the discount by 39 and it will get you 11.7. 11.7 is the money of discount so now all you have to do is subtract 11.7 from 39 and you shall get 27.3.
7 0
3 years ago
What point on the parabola y=3-x^2 is closest to the point ​(3​,3​)?
OverLord2011 [107]
3+x-Y hope it helps :DD
6 0
3 years ago
1.)
VashaNatasha [74]

Answer:

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

Step-by-step explanation:

1.

\frac{z}{-5}+1=4

Add -1 both sides,

\frac{z}{-5}+1-1=4-1\\\frac{z}{-5}=3

Multiply both sides by -5,

\frac{z}{-5}\times-5=3\times-5\\z=-15

2.

Distribute 3 in p+2 and then add -6p and -6 both sides.

3(p+2)=6p-15\\3\times p+3\times2 = 6p-15\\3p+6=6p-15\\3p-6p=-15-6\\-3p=-21\\p=\frac{-21}{-3}=7

3.

\frac{h-7}{2}=3(h+8)

Multiply both sides by 2,

\frac{h-7}{2}\times2=3(h+8)\times2\\h-7=6(h+8)\\h-7=6h+48

Add -6h and 7 both sides,

h-6h-7+7=6h-6h+48+7\\-5h=55\\h=\frac{55}{-5}\\h=-11

4.

4t+2-5=3(t+7)-9\\4t-3=3t+21-9\\4t-3=3t+12

Add -3t and 3 both sides.

4t-3t-3+3=3t-3t+12+3\\t=15

5.

2(q-4)=4(q-8)\\2q-8=4q-32

Add -2q and 8 both sides.

2q-8-4q+8=4q-4q-32+8\\-2q=-24\\q=\frac{-24}{-2}\\q=12

Therefore,

1. z = -15

2. p = 7

3. h = -11

4. t = 14

5. q = 12

4 0
4 years ago
Other questions:
  • What is the definition of point of tangency? in Geometry
    15·2 answers
  • If a pier is 200 meters long and each board is 80 centimeters wide, how many boards are in the pier?
    9·2 answers
  • John what's a build a slide for his daughters tree house. The slide is made from aluminium material that is cut from a roll. The
    11·1 answer
  • In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
    5·1 answer
  • What is -3 - 15. can you please solve this for me.
    7·1 answer
  • What is the solution set of the system of inequalities 5x<8+4y and 2y≤6?
    11·1 answer
  • graph each equation identify the conic section. any lines of symmetry, and the domain and range. x^2+y^2=4
    12·1 answer
  • Please Help and give an explanation!!!
    5·1 answer
  • PLS PLS PLS HELP I WILL GIVE BRAINLIEST!!!
    12·2 answers
  • Find the area of the trapezoid
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!