<u>Answer-</u>
<em>$2000</em><em> were invested at 5%</em>
<u>Solution-</u>
Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%
We know that,

Putting the values,


And


According to the question,







Therefore, $2000 were invested at 5%
Using translation concepts, the ordered pair that describes the location of W'' is: W''(-6,-4).
<h3>What is a translation?</h3>
A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.
The rule for a reflection over the y-axis is:
(x,y) -> (-x,y).
Hence:
W'(-6,4).
The rule for a reflection over the x-axis is:
(x,y) -> (x, -y).
Hence:
W''(-6,-4).
More can be learned about translation concepts at brainly.com/question/4521517
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Answer:
1/4
Step-by-step explanation:
The classical probability assessment works based on the principle that the probability of an event occurring is equal to the number of times the event occurs divided by total number of outcomes.
That is:
P(A) = n(A) / N
Therefore, the probability that the next customer will buy a computer will be:
P(c) = 25 / 100 = 1/4
The amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
<h3>What is compound interest?</h3>
Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-
![A=P[1+\dfrac{r}{n}]^{nt}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7Bn%7D%5D%5E%7Bnt%7D)
a) The amount in the bank after 6 years if interest is compounded annually.
![A=P[1+\dfrac{r}{1}]^{t}\\\\\\A=6000[1+\dfrac{0.01}{1}]^{ 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B1%7D%5D%5E%7Bt%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B1%7D%5D%5E%7B%20%206%7D)
A= $6369
b) The amount in the bank after 6 years if interest is compounded quarterly.
![A=P[1+\dfrac{r}{4}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{4}]^{4\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B4%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B4%7D%5D%5E%7B4%5Ctimes%206%7D)
A= $6090
c ) The amount in the bank after 6 years if interest is compounded monthly.
![A=P[1+\dfrac{r}{12}]^{4t}\\\\\\A=6000[1+\dfrac{0.01}{12}]^{12\times 6}](https://tex.z-dn.net/?f=A%3DP%5B1%2B%5Cdfrac%7Br%7D%7B12%7D%5D%5E%7B4t%7D%5C%5C%5C%5C%5C%5CA%3D6000%5B1%2B%5Cdfrac%7B0.01%7D%7B12%7D%5D%5E%7B12%5Ctimes%206%7D)
A=$6030
Hence the amount for the investment of $6000 will be a.$6369 b. $6090 and c.$6030.
To know more about Compound interest follow
brainly.com/question/24924853
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Answer:
you can say he bought 2 small notebooks and 4 big notebooks
Step-by-step explanation:
we have 52 dollars here
so if we have 4 large notebooks that will cost 40 dollars and if we have 2 small notebooks on addiction to that, that will cost 12 more dollars
now adding up 40 and 12 we get $52 !