You can use 10 blocks by having 1 ten and 6 ones and then divide it into groups of 3 when you do that you are kind of subtracting when you take away 3 away each time. After that you multiply it, so you think of whatever times 3 is 16 which is 15 r1. Then your answer should be 30.
All you have to do is put 36/125. This will get you .288. When rounded to the nearest percent, it is 28%.
No, it is not true
Lets do an example:
4 divided by 2 divided by 1 equals 2, while 2 divided by 1 divided by 4 equals 0.5
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
The answer to your question would be that 101.7 is the freezing point of phosphorous.
