Evaluate the expression for s=4 and t=8
2 answers:
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Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or ft
= ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W =
=
=
= 9()²
= 7.56 lb-ft
Answer:
<h2>B. The slope is 5 and (2, 4) is on the line.</h2>Step-by-step explanation:
The point-slope form of an equation of a line:
<em>m</em><em> - slope</em>
<em>(x₁, y₁)</em><em> - point</em>
<em />
We have the equation:
Therefore
<em>m = 5</em>
<em>(x₁, y₁) = (2, 4)</em>
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