2 years ago

Solve for g. -7g − 8 = -6g

Mathematics

1 answer:

den301095 [7]2 years ago

8 0

Answer:

G=-8

Step-by-step explanation:

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(1,5) (2,7)<br> How to find the equation of the line passing through the given points

IceJOKER [234]

Answer:

y = 2x - 3

Step-by-step explanation:

to do this problem, we will use the following formula to find the slope of the line

(y2 - y1) / (x2 - x1)

(1,5) (2,7)

(7 - 5) / (2 - 1)

2 / 1

2 = m

next, we will substitute the slope and one of the points into the slope-intercept form (y = mx + b) and solve for b to find the y-intercept

y = mx + b

7 = (5)(2) + b

7 = 10 + b

-3 = b

finally, we put it all together into one equation

y = 2x - 3

7 0

2 years ago

Rewrite 2+(1/b-2) = (3b/b+2) as a proportion. Which of these proportions is equivalent to the original equation?

lorasvet [3.4K]

Answer: c for the first part

1,6 for the second

nether for the third

Step-by-step explanation:

all on edg

7 0

2 years ago

Read 2 more answers

write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)

gladu [14]

Find midpoint of segment.
(-1,1), (7,-5)
$x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2$

Find slope of line which passes through (-1,1) and (7,-5).
$m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}$

The slope of perpendicular line is negative reciprocal value of m.
$m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}$

Write quation of line which slope is $\frac{4}{3}$ and passes throug the point (3,-2).
$m=\frac{4}{3},x_1=3,y_1=-2
\\y-y_1=m(x-x_1)
\\
\\y-(-2)=\frac{4}{3}(x-3)
\\
\\y+2=\frac{4}{3}x-\frac{8}{3}
\\
\\3y+6=4x-8
\\4x-3y-14=0$

3 0

3 years ago

If guy walks from his house to school and back,how far does he walk?

Serga [27]

He walked the same distance to school and back home.
I hope this helped! :-)

8 0

3 years ago

Read 2 more answers

The height of a cylindrical can is 4 7/16 inches and the radius is 3 inches. Which measurement is closest to the total surface a

-Dominant- [34]

Answer:

140.19