P(a U b) = p(a) + p(b) - p(a ∩ b)
<=>
p(a ∩ b) = p(a) + p(b) - p(a U b)
I let you do the maths :)
The awnser to that question is 80000
Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer: A)
Explanation: 10-3=7
-17 -35
-3 -3
-2 0
-31 -87
17 57
